Precalculus

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1: log(base3) 81= 2: log(base16) 4= 3: log(base 1/2) ?2= 4: log (1/?10)= 5: log (mn/p)= 6: log ?mn= 7: log(base5) (2x+3) = log(base5) 3 8: -2 log(base4) x = log(base4) 9 9: 3 log(base2) x = -log(base2) 27 10: 2 log(base 3) (x+4) – log(base3) 9=2 11: log(base4) x + log(base4) (x-3) = 1 12: log(base2) (x+11) + log(base2) (x+7) = 5 13: 3^x=14 14: 2^-x=1.5 15: 2^x+1 = 5^1-2x 16: (4/3)^1-x = 5^x 17: log(base a) x+ log(base a) (x-2) = log(base a) (x+4) 18: log(base 4) (x^2 – 9) – log(base4) (x+3) = 3 19: log(base9) x+3 log(base3) x = 14 20: log(base 2) x^log(base2)x = 4 21: Ln x = 4 22: Ln (1/3?e) = 23: Ln(x/e) = -1 24: x^3=e Answer